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Application of Cauchy-Schwarz Inequality in Work Done

A 3D coordinate system grid showing an orange Force Vector F and a blue Displacement Vector d, with an angle marked between them.
The geometric relationship between force and displacement vectors as represented in three-dimensional space.

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Problem: Application of Cauchy-Schwarz Inequality in Work Done

In classical mechanics, the work done ##W## by a constant force ##\vec{F} = F_x \hat{i} + F_y \hat{j}## acting on a particle undergoing a displacement ##\vec{d} = d_x \hat{i} + d_y \hat{j}## is defined as the scalar (dot) product ##W = \vec{F} \cdot \vec{d} = F_x d_x + F_y d_y##.

Quantity Mathematical Representation Physical Meaning
Force Vector ##\vec{F} = F_x \hat{i} + F_y \hat{j}## The push or pull acting on a particle
Displacement Vector ##\vec{d} = d_x \hat{i} + d_y \hat{j}## The change in position of the particle
Work Done ##W = \vec{F} \cdot \vec{d}## Energy transferred by the force over displacement
Using the Cauchy-Schwarz inequality for vectors in ##\mathbb{R}^2##, establish the mathematical upper bound for the magnitude of the work done ## W ## in terms of the magnitudes of the force and displacement vectors. Furthermore, determine the exact physical condition under which this upper bound is achieved.

Worked Solution & Step-by-Step Explanation

To determine the upper bound of the work done, we rely on the Cauchy-Schwarz inequality. This inequality is a fundamental theorem in linear algebra and vector calculus, providing a tight bound on the inner product of two vectors.

Step 1: The Cauchy-Schwarz Inequality Definition

For any two sequences of real numbers ##(a_1, a_2)## and ##(b_1, b_2)##, the Cauchy-Schwarz inequality states:

###(a_1 b_1 + a_2 b_2)^2 \le (a_1^2 + a_2^2)(b_1^2 + b_2^2)###

By taking the non-negative square root of both sides, we obtain the expression for the absolute value:

### a_1 b_1 + a_2 b_2 \le \sqrt{a_1^2 + a_2^2} \cdot \sqrt{b_1^2 + b_2^2}###
Form Mathematical Expression Context
Absolute Value Form
## a_1 b_1 + a_2 b_2 \le \sqrt{a_1^2 + a_2^2} \cdot \sqrt{b_1^2 + b_2^2}##
Squared Form ##(a_1 b_1 + a_2 b_2)^2 \le (a_1^2 + a_2^2)(b_1^2 + b_2^2)## Original inequality for sequences

Derived by taking non-negative square root

Vector Dot Product Equivalent

## \vec{A} \cdot \vec{B} \le \ \vec{A}\ \ \vec{B}\ ##

General vector form (implied by inequality)

Step 2: Mapping to Physical Variables

We define our force vector components as ##a_1 = F_x## and ##a_2 = F_y##, and our displacement vector components as ##b_1 = d_x## and ##b_2 = d_y##. Substituting these into the inequality yields:

Cauchy-Schwarz Variable Physical Variable Description
##a_1## ##F_x## X-component of the Force Vector
##a_2## ##F_y## Y-component of the Force Vector
##b_1## ##d_x## X-component of the Displacement Vector
##b_2## ##d_y## Y-component of the Displacement Vector
### F_x d_x + F_y d_y \le \sqrt{F_x^2 + F_y^2} \cdot \sqrt{d_x^2 + d_y^2}###

Step 3: Identification of Physical Quantities

The left-hand side of the inequality is the definition of the work done, ##W = \vec{F} \cdot \vec{d}##. Thus, we represent the absolute value as ## W ##. On the right-hand side, we recognize the Euclidean norms (magnitudes) of the force and displacement vectors:
###\ \vec{F}\ = \sqrt{F_x^2 + F_y^2}###
###\ \vec{d}\ = \sqrt{d_x^2 + d_y^2}###

Consequently, the inequality simplifies to:

### W \le \ \vec{F}\ \ \vec{d}\ ###

This establishes that the magnitude of the work done can never exceed the product of the magnitudes of the force and the displacement.

Step 4: Determining the Condition for Equality

The equality holds if and only if the vectors are linearly dependent (i.e., proportional). Mathematically, this occurs when:

###\dfrac{F_x}{d_x} = \dfrac{F_y}{d_y} = k###

where ##k## is a non-zero scalar constant. In physical terms, this implies that the force vector ##\vec{F}## is parallel or antiparallel to the displacement vector ##\vec{d}##.

Condition Mathematical Meaning Physical Interpretation

:--- :--- :---

##k > 0## ##\vec{F} = k\vec{d}## Force is in the same direction as displacement; ##\theta = 0^\circ##

##k < 0## ##\vec{F} = k\vec{d}## Force is in the opposite direction; ##\theta = 180^\circ##

## W = \ \vec{F}\
Since the standard definition of work is ##W = \ \vec{F}\ \ \vec{d}\ \cos\theta##, the Cauchy-Schwarz inequality confirms that ## W ## reaches its maximum possible value when ##\cos\theta = \pm 1##. This rigorous approach confirms that the most efficient transfer of energy (maximum work) occurs when the force is applied directly along the line of motion.

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