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Problem: AM-GM Inequality for Minimum Power Dissipation
An electrical source is connected to a circuit containing two variable resistors ##R_1## and ##R_2## in series. If the product of the two resistances is held constant such that ##R_1 R_2 = C##, where ##C## is a positive constant, determine the minimum value of the total series resistance ##R_s = R_1 + R_2## using the Arithmetic Mean-Geometric Mean (AM-GM) inequality. Provide a rigorous mathematical proof.
Worked Solution & Step-by-Step Explanation
1. Understanding the Physical and Mathematical Constraints
In passive electrical circuits, resistance is a physical quantity that represents the opposition to the flow of electric current. By physical laws, the resistance of standard passive components must be non-negative real numbers. Therefore, we establish our domain constraints as:
We are given that the product of these two positive resistances is constrained to a constant value ##C##:
The total equivalent resistance of the two resistors connected in series, denoted as ##R_s##, is given by the sum of their individual resistances:
Our objective is to find the minimum possible value of ##R_s## under the given product constraint using the Arithmetic Mean-Geometric Mean (AM-GM) inequality.
Variable Definitions for AM-GM Power Optimization
Key parameters and their constraints used to model minimum power dissipation in resistive circuits.
| Parameter | Physical Meaning | Mathematical Domain |
|---|---|---|
| R1 | Resistance of the first variable resistor | R1 > 0 |
| R2 | Resistance of the second variable resistor | R2 > 0 |
| C | Constant product constraint of resistances | C > 0 |
| Rs | Total equivalent series resistance | Rs = R1 + R2 |
- The AM-GM inequality is applied to minimize Rs given the constraint R1 * R2 = C.
- All variables must remain positive to maintain physical validity in electrical circuits.
2. Rigorous Proof of the AM-GM Inequality for Two Variables
To ensure mathematical rigor, we first prove the AM-GM inequality for two positive real variables ##x_1## and ##x_2##. Let ##x_1, x_2 \in \mathbb{R}^+##.
Consider the square of the difference between their square roots. Since the square of any real number is non-negative, we can write:
Expanding the left-hand side of this inequality using the algebraic identity ##(a - b)^2 = a^2 - 2ab + b^2##, we obtain:
Since ##x_1## and ##x_2## are positive, ##(\sqrt{x_1})^2 = x_1## and ##(\sqrt{x_2})^2 = x_2##. Substituting these back into the expression yields:
Adding ##2\sqrt{x_1 x_2}## to both sides of the inequality:
Dividing both sides by ##2##, we arrive at the standard formulation of the AM-GM inequality for two variables:
Analyzing the Condition for Equality
The equality holds if and only if the initial squared term is zero:
Taking the square root of both sides:
Squaring both sides yields the final equality condition:
| Inequality Type | Mathematical Expression | Condition for Equality |
|---|---|---|
| Arithmetic Mean (AM) | ##\dfrac{R_1 + R_2}{2}## | Holds for all ##R_1, R_2 > 0## |
| Geometric Mean (GM) | ##\sqrt{R_1 R_2}## | Holds for all ##R_1, R_2 > 0## |
| AM-GM Relation | ##\dfrac{R_1 + R_2}{2} \ge \sqrt{R_1 R_2}## | ##R_1 = R_2## |
3. Application of AM-GM to the Circuit Problem
We map our physical variables directly to the proven inequality. Let ##x_1 = R_1## and ##x_2 = R_2##. Since ##R_1 > 0## and ##R_2 > 0##, we apply the AM-GM inequality:
Multiplying both sides of the inequality by ##2##:
We substitute the expression for total series resistance ##R_s = R_1 + R_2## and the given constraint ##R_1 R_2 = C## into the inequality:
This inequality establishes that the total series resistance ##R_s## is bounded below by ##2\sqrt{C}##. Therefore, the minimum value of ##R_s## is:
4. Determining the Minimizing Resistance Values
The minimum value ##R_{s,\text{min}}## is achieved when the condition for equality in the AM-GM inequality is satisfied. As proven in Section 2, equality holds if and only if the terms are equal:
Using the constraint equation ##R_1 R_2 = C##, we substitute ##R_2## with ##R_1##:
Since resistance must be positive (##R_1 > 0##), we take the positive square root:
Consequently, because ##R_2 = R_1##, we find:
Thus, the minimum total series resistance is achieved when both variable resistors are set to equal values of ##\sqrt{C}##.
AM-GM Inequality for Minimum Power Dissipation
This table demonstrates how resistance distribution impacts total series resistance while maintaining a constant product.
| Scenario | R1 (Ω) | R2 (Ω) | Product (Ω²) | Total Resistance (Ω) |
|---|---|---|---|---|
| Highly Asymmetric | 1 | 100 | 100 | 101 |
| Moderately Asymmetric | 4 | 25 | 100 | 29 |
| Symmetric (Optimal) | 10 | 10 | 100 | 20 |
- The total series resistance is minimized when R1 equals R2.
- The product R1R2 remains constant at 100 Ω² across all scenarios.
5. Physical Significance in Power Dissipation
In electrical engineering, if this series combination is connected to a constant voltage source ##V##, the total power dissipated by the circuit is given by:
To minimize the power dissipation of the circuit for a fixed voltage source, we must maximize the total resistance ##R_s##. Conversely, to maximize the power dissipation (or to design for maximum current flow), we minimize ##R_s##. The minimum resistance occurs when ##R_1 = R_2 = \sqrt{C}##, yielding the maximum power dissipation state for a constant voltage supply:
This demonstrates how algebraic optimization tools like the AM-GM inequality directly govern the limits of physical systems and energy efficiency calculations in circuit design.
RESOURCES
- What's a harmonic mean and why does everyone joke about it?reddit.comNov 22, 2022 ... I only know this because I did a number of math competitions in high school and one of the inequalities…
- Why is equivalent resistance in parallel circuit always less than each ...physics.stackexchange.comSep 27, 2014 ... R_{n}$ or that $R_{ev}$ is less than the Resistor $R_{min}$, which has the least resistance of all the individual resistors?…
- Proof of AM-GM inequality for $n=3$: $frac{a+b+c}{3}geqsqrt[3]{abc}math.stackexchange.comJun 27, 2016 ... If a,b or c equals zero the inequality is trivial. Hence we may assume: (a,b,c)=(eA,eB,eC). without loss of generality, and…
- An Inequality Indicator for High-Resistance Connection Fault ...tethys-engineering.pnnl.govJan 4, 2023 ... AM-GM inequalities can be combined to form a total inequality as follows: ... When the stator currents are balanced, κ…
- Find maximum value of $(1 + sin x)(1 + cos x) - Math Stack Exchangemath.stackexchange.comAug 22, 2020 ... You can find the solutions to x and check if each of them results in a maximum or minimum. ...…
- An Inequality Indicator for High-Resistance Connection Fault ... - MDPImdpi.comThe inequality indicator can be equivalent to several AM-GM inequalities ... When the stator currents are balanced, κ takes to be the minimum, which…
- The resistance of the series combination of two resistances is S ...allen.in... AM-GM inequality Using the Arithmetic Mean-Geometric Mean (AM-GM) inequality ... minimum possible value of ( n ) is 4.
- Infinite Lewis Weights in Spectral Graph Theory - arXivarxiv.orgFeb 12, 2023 ... quantities should always be small comes from the scalar inequality min{x,(log x)0} = 1. ... use AM − GM inequality…
- Did you know that over half of all Members of Congress are ...facebook.comDec 17, 2025 ... ... am honored to be here, and I can't do this work without you ... https://inequality.org/research/minimum-wage/ This makes some sense ...
- Harmonic mean - Wikipediaen.wikipedia.org... minimum of its arguments: for positive arguments, min ( x 1 … x n ) ≤ H ... HM-GM-AM-QM inequalities · Harmonic mean…
![[Easy] AM-GM Inequality for Minimum Power Dissipation_img_0 A 3D graphic of two glowing neon resistor coils on a dark background, labeled R1 in pink on the left and R2 in blue on the right, connected to intersecting circuit lines.](https://jupiterscience.com/wp-content/uploads/2026/06/easy-am-gm-inequality-for-minimum-power-dissipation-img-0.webp)




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