Q: Problem Statement

A solid cylinder of mass $ m = 2 \, \text{kg} $ and radius $ r = 0.1 \, \text{m} $ rolls down an inclined plane without slipping. Find the acceleration of the cylinder.

Q: Solution

The moment of inertia for a solid cylinder is $ I = \frac{1}{2} mr^2 $. Substitute this into the acceleration formula:

Question 1

Problem Statement

Accepted Answer

A solid cylinder of mass $ m = 2 \, \text{kg} $ and radius $ r = 0.1 \, \text{m} $ rolls down an inclined plane without slipping. Find the acceleration of the cylinder.

Question 2

Concepts Involved

Accepted Answer

For rolling motion without slipping, the acceleration is given by $ a = \frac{g \sin \theta}{1 + \frac{I}{mr^2}} $, where $ I $ is the moment of inertia of the cylinder.

Question 3

Solution

Accepted Answer

The moment of inertia for a solid cylinder is $ I = \frac{1}{2} mr^2 $. Substitute this into the acceleration formula:

Question 4

Key Takeaways

Accepted Answer

Understanding the moment of inertia and its role in rotational motion is crucial. Always consider the angle of inclination in problems involving inclined planes.

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10 Physics Numerical Problems with Solutions for IIT JEE Preparation

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10 Physics Numerical Problems with Solutions for IIT JEE Preparation

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